72=k(2^2)(3^2)

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Solution for 72=k(2^2)(3^2) equation: 



72=k(2^2)(3^2)

We move all terms to the left:

72-(k(2^2)(3^2))=0

determiningTheFunctionDomain
-k2^23^2+72=0

We move all terms containing k to the left, all other terms to the right

-k2^23^2=-72

k=-72/1

k=-72

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